I’m using: SWI-Prolog version 8.4.3 for x64-win64 i have a list of predicates : ListP = [ patient(201, 4, 2, inTime), patient(202, 3, 2, late), patient(203, 2, 3, late), patient(204, 1, 3, late), patient(204, 1, 4, inTime), patient(203, 2, 4, late), patient(204, 1, 5, inTime),…

It happens because bagof/3 fails if it cannot find any answer (in contrast, findall/3 succeeds with an empty list). It’s not easy to fix your code, because you’re using bagof to produce the distinct values. Maybe count_occurrences(ListP,CountInTime) :- map_list_to_pairs(arg(3),ListP,Keyed), …

Count number of occurrence in a list with condition

Help!

brebs August 2, 2022, 6:08pm 2

Use Sorting predicates in PROLOG - #19 by brebs and adapt it to count.

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Count number of occurrence in a list with condition

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