I came across this code, which I assume will be faster than iterating one element at a time. nth0_det(0, [Elem|_], Elem) :- !. nth0_det(1, [_,Elem|_], Elem) :- !. nth0_det(2, [_,_,Elem|_], Elem) :- !. nth0_det(3, [_,_,_,Elem|_], Elem) :- !. nth0_det(4, [_,_,_,_,Elem|_], Elem) :- !. nth0_det(5, [_,_…

Nth0/3 implementaion in swi-prolog

rajashekar November 29, 2020, 1:39pm 3

I do not understand how the limit on number of parameters will apply in this situation.

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