I came across this code, which I assume will be faster than iterating one element at a time. nth0_det(0, [Elem|_], Elem) :- !. nth0_det(1, [_,Elem|_], Elem) :- !. nth0_det(2, [_,_,Elem|_], Elem) :- !. nth0_det(3, [_,_,_,Elem|_], Elem) :- !. nth0_det(4, [_,_,_,_,Elem|_], Elem) :- !. nth0_det(5, [_,_…

Nth0/3 implementaion in swi-prolog

rajashekar November 29, 2020, 1:39pm 3

I do not understand how the limit on number of parameters will apply in this situation.

Topic		Replies	Views
Iam trying to generate all n-element sublists of a given list n is one of the arguments I have to use enforced backtracking but not getting the idea Help!	12	778	September 16, 2020
Elevator Example and the Prolog VM Nice to know on-topic-only	39	5875	August 19, 2021
Logical Loop Split Topic	9	1383	September 8, 2019
Constrained traversal in Prolog - a short article Nice to know	1	87	November 18, 2024
Ann: SWI-Prolog 8.3.21 Releases	3	622	April 1, 2021