Hello,
Suppose you have a predicate that in its body has 5 findall calls, one performed after the other leading to 5 lists, Now suppose you want to append those 5 lists as a result of the predicate.
One can write four appends to combine them all and return the combined list. I wonder what the most efficient way to combine such N lists are.
I am wondering if one can do better, somehow, than simply appending them, e.g. with difference lists, altough each list is generated by findall…
Perhaps best if there was a findall version that generates a difference list as a result …
thanks,
Dan